jonesn7 jonesn7

01-03-2020
Mathematics

contestada

Find cosB tanB and sinB BRANLIEST ASAP TY!!!

Find cosB tanB and sinB BRANLIEST ASAP TY class=

Respuesta :

01-03-2020

Answer:

Given below

Step-by-step explanation:

[tex] \cos(b) = \frac{8}{17} \\ \\ \tan(b) = \frac{15}{8} \\ \\ \sin(b) = \frac{15}{17} [/tex]

Since cos B = adjacent side / hypotenuse

Tan B = opposite side / adjacent side

Sin B = opposite side/ hypotenuse

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